What is the answer to 7^{x+1}=3^{x+2} ?

The answer to 7^{x+1}=3^{x+2} is x=(2ln(3)-ln(7))/(ln(7)-ln(3))

Solve for x: 7^{x+1}=3^{x+2}

The solution is x=(2ln(3)-ln(7))/(ln(7)-ln(3))

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7^{x + 1} = 3^{x + 2}

x = \frac{2 ln ( 3 ) - ln ( 7 )}{ln ( 7 ) - ln ( 3 )}

Solution steps

7^{x + 1} = 3^{x + 2}

Apply exponent rules

(x + 1) ln (7) = (x + 2) ln (3)

Solve

(x + 1) ln (7) = (x + 2) ln (3) : x = \frac{2 ln ( 3 ) - ln ( 7 )}{ln ( 7 ) - ln ( 3 )}

x = \frac{2 ln ( 3 ) - ln ( 7 )}{ln ( 7 ) - ln ( 3 )}

4^{x} = 8^{x + 1}

5^{x^{2}} = 2 5^{4 - x}

3^{x + 1} = 3^{5}

3^{2 x - 1} = 81

128 = \frac{5 ^{2 n - 5}}{2 ^{4 n}}

What is the answer to 7^{x+1}=3^{x+2} ?
The answer to 7^{x+1}=3^{x+2} is x=(2ln(3)-ln(7))/(ln(7)-ln(3))
Solve for x: 7^{x+1}=3^{x+2}
The solution is x=(2ln(3)-ln(7))/(ln(7)-ln(3))