What is the answer to 4(2^{2x})=8(2^x)-4 ?

The answer to 4(2^{2x})=8(2^x)-4 is x=0

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4(2^{2x})=8(2^x)-4

4 (2^{2 x}) = 8 (2^{x}) - 4

x = 0

Solution steps

4 (2^{2 x}) = 8 (2^{x}) - 4

Apply exponent rules

4 (2^{x})^{2} = 8 \cdot 2^{x} - 4

Rewrite the equation with

2^{x} = u

4 (u)^{2} = 8 u - 4

Solve

4 u^{2} = 8 u - 4 : u = 1

u = 1

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 1 : x = 0

x = 0

e^{x^{2} - x - 2} = 1

4^{x^{2}} = 2^{2 x}

7^{8} = 7^{8} \cdot 7^{x}

2 e^{2 x} = 2

3^{x} = 3

What is the answer to 4(2^{2x})=8(2^x)-4 ?
The answer to 4(2^{2x})=8(2^x)-4 is x=0
Solve for x: 4(2^{2x})=8(2^x)-4
The solution is x=0