What is the answer to 25^{x^2-3x+7}=125^{x-2} ?

The answer to 25^{x^2-3x+7}=125^{x-2} is No Solution for x\in\mathbb{R}

Solve for x: 25^{x^2-3x+7}=125^{x-2}

The solution is No Solution for x\in\mathbb{R}

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Popular >

2 5^{x^{2} - 3 x + 7} = 12 5^{x - 2}

No Solution for x \in R

Solution steps

2 5^{x^{2} - 3 x + 7} = 12 5^{x - 2}

Apply exponent rules

2 (x^{2} - 3 x + 7) = 3 (x - 2)

Solve

2 (x^{2} - 3 x + 7) = 3 (x - 2) :

No Solution for

x \in R

No Solution for x \in R

4^{x} - 9 \cdot 2^{x - 1} + 2 = 0

2 e^{2 x} - e^{x} = 0

0 = e^{- x}

e^{y} = 9

e^{2 x} - 6 e^{x} + 8 = 0

What is the answer to 25^{x^2-3x+7}=125^{x-2} ?
The answer to 25^{x^2-3x+7}=125^{x-2} is No Solution for x\in\mathbb{R}
Solve for x: 25^{x^2-3x+7}=125^{x-2}
The solution is No Solution for x\in\mathbb{R}