What is the answer to 4^{2x+6}=64^{2x-4} ?

The answer to 4^{2x+6}=64^{2x-4} is x= 9/2

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4^{2x+6}=64^{2x-4}

4^{2 x + 6} = 6 4^{2 x - 4}

x = \frac{9}{2}

Solution steps

4^{2 x + 6} = 6 4^{2 x - 4}

Apply exponent rules

2 x + 6 = 3 (2 x - 4)

Solve

2 x + 6 = 3 (2 x - 4) : x = \frac{9}{2}

x = \frac{9}{2}

5^{x} = 16

e^{x} + 15 e^{- x} - 8 = 0

3^{x - 9} = 8 1^{5 x + 1}

3^{1 - 2 x} = 243

2^{x} + 2^{x + 1} = \frac{3}{2}

What is the answer to 4^{2x+6}=64^{2x-4} ?
The answer to 4^{2x+6}=64^{2x-4} is x= 9/2
Solve for x: 4^{2x+6}=64^{2x-4}
The solution is x= 9/2