What is the answer to 27^{5x-4}=81^{7x-2} ?

The answer to 27^{5x-4}=81^{7x-2} is x=-4/13

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27^{5x-4}=81^{7x-2}

2 7^{5 x - 4} = 8 1^{7 x - 2}

x = - \frac{4}{13}

Decimal Notation

x = - 0.30769 \dots

Solution steps

2 7^{5 x - 4} = 8 1^{7 x - 2}

Apply exponent rules

3 (5 x - 4) = 4 (7 x - 2)

Solve

3 (5 x - 4) = 4 (7 x - 2) : x = - \frac{4}{13}

x = - \frac{4}{13}

5^{x - 1} = 2 + \frac{3}{5 ^{x - 2}}

e^{3 x} - e^{2 (3 x)} = 0

1024 = 2^{x}

1 0^{x} = 100

What is the answer to 27^{5x-4}=81^{7x-2} ?
The answer to 27^{5x-4}=81^{7x-2} is x=-4/13
Solve for x: 27^{5x-4}=81^{7x-2}
The solution is x=-4/13