What is the answer to 2^{2x+4}-9(2^x)=0 ?

The answer to 2^{2x+4}-9(2^x)=0 is x=(2ln(3)-4ln(2))/(ln(2))

Solve for x: 2^{2x+4}-9(2^x)=0

The solution is x=(2ln(3)-4ln(2))/(ln(2))

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2^{2 x + 4} - 9 (2^{x}) = 0

x = \frac{2 ln ( 3 ) - 4 ln ( 2 )}{ln ( 2 )}

Decimal Notation

x = - 0.83007 \dots

Solution steps

2^{2 x + 4} - 9 (2^{x}) = 0

Add

9 \cdot 2^{x}

to both sides

2^{2 x + 4} - 9 \cdot 2^{x} + 9 \cdot 2^{x} = 0 + 9 \cdot 2^{x}

Simplify

2^{2 x + 4} = 9 \cdot 2^{x}

Apply exponent rules

(2 x + 4) ln (2) = ln (9) + x ln (2)

Solve

(2 x + 4) ln (2) = ln (9) + x ln (2) : x = \frac{2 ln ( 3 ) - 4 ln ( 2 )}{ln ( 2 )}

x = \frac{2 ln ( 3 ) - 4 ln ( 2 )}{ln ( 2 )}

8 x = 1 6^{x}

0.9 = \frac{0.1}{0.5 5 ^{x}}

(3^{x}) (4^{2 x + 1}) = 6^{x + 2}

\frac{1 1 ^{x}}{1 1 ^{3}} = 1 1^{2}

5^{2 x} - 5^{x} - 12 = 0

What is the answer to 2^{2x+4}-9(2^x)=0 ?
The answer to 2^{2x+4}-9(2^x)=0 is x=(2ln(3)-4ln(2))/(ln(2))
Solve for x: 2^{2x+4}-9(2^x)=0
The solution is x=(2ln(3)-4ln(2))/(ln(2))