What are the solutions to the equation 8x^2-8x+2=0 ?

The solutions to the equation 8x^2-8x+2=0 are x= 1/2

Find the zeros of 8x^2-8x+2=0

The zeros of 8x^2-8x+2=0 are x= 1/2

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8 x^{2} - 8 x + 2 = 0

x = \frac{1}{2}

Solution steps

8 x^{2} - 8 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

(- 8)^{2} - 4 \cdot 8 \cdot 2 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 8}

x = \frac{- ( - 8 )}{2 \cdot 8}

\frac{- ( - 8 )}{2 \cdot 8} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

2 a^{2} + 7 ab + 3 b^{2}

\frac{5 x - 1}{3} - \frac{2 x - 4}{5} = - 1

x^{4} + x^{3} - 7 x^{2} - 5 x + 10

\frac{1}{2} \cdot \frac{1}{3}

5 k + 1 \leq - 4

What are the solutions to the equation 8x^2-8x+2=0 ?
The solutions to the equation 8x^2-8x+2=0 are x= 1/2
Find the zeros of 8x^2-8x+2=0
The zeros of 8x^2-8x+2=0 are x= 1/2