What is the answer to 5*20^x=8*2^x ?

The answer to 5*20^x=8*2^x is x=(3ln(2)-ln(5))/(ln(10))

Solve for x: 5*20^x=8*2^x

The solution is x=(3ln(2)-ln(5))/(ln(10))

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5 \cdot 2 0^{x} = 8 \cdot 2^{x}

x = \frac{3 ln ( 2 ) - ln ( 5 )}{ln ( 10 )}

Decimal Notation

x = 0.20411 \dots

Solution steps

5 \cdot 2 0^{x} = 8 \cdot 2^{x}

Apply exponent rules

ln (5) + x ln (20) = ln (8) + x ln (2)

Solve

ln (5) + x ln (20) = ln (8) + x ln (2) : x = \frac{3 ln ( 2 ) - ln ( 5 )}{ln ( 10 )}

x = \frac{3 ln ( 2 ) - ln ( 5 )}{ln ( 10 )}

t, f = a e^{- a t} u (t)

2^{4 x} - 5 \cdot 2^{2 x} + 4 = 0

9 \cdot 2 7^{x} = 27

1.7 = 240 (0.5)^{\frac{x}{19}}

n, (z^{2})^{n} = z^{10}

What is the answer to 5*20^x=8*2^x ?
The answer to 5*20^x=8*2^x is x=(3ln(2)-ln(5))/(ln(10))
Solve for x: 5*20^x=8*2^x
The solution is x=(3ln(2)-ln(5))/(ln(10))