What is the answer to 3^{x-2}=5^{x+1} ?

The answer to 3^{x-2}=5^{x+1} is x=(ln(45))/(ln(3)-ln(5))

Solve for x: 3^{x-2}=5^{x+1}

The solution is x=(ln(45))/(ln(3)-ln(5))

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3^{x - 2} = 5^{x + 1}

x = \frac{ln ( 45 )}{ln ( 3 ) - ln ( 5 )}

Decimal Notation

x = - 7.45198 \dots

Solution steps

3^{x - 2} = 5^{x + 1}

Apply exponent rules

(x - 2) ln (3) = (x + 1) ln (5)

Solve

(x - 2) ln (3) = (x + 1) ln (5) : x = \frac{ln ( 45 )}{ln ( 3 ) - ln ( 5 )}

x = \frac{ln ( 45 )}{ln ( 3 ) - ln ( 5 )}

e^{- x} = 2

6 4^{7 x - 8} = 1

e^{- x^{2}} - 2 e^{- x^{2}} x^{2} = 0

e^{- 6 x} = 0.15

x^{l n (x)} = e^{(l n (x))^{3}}

What is the answer to 3^{x-2}=5^{x+1} ?
The answer to 3^{x-2}=5^{x+1} is x=(ln(45))/(ln(3)-ln(5))
Solve for x: 3^{x-2}=5^{x+1}
The solution is x=(ln(45))/(ln(3)-ln(5))