What is the answer to 8^{2x+1}=4^{1-x} ?

The answer to 8^{2x+1}=4^{1-x} is x=-1/8

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8^{2x+1}=4^{1-x}

8^{2 x + 1} = 4^{1 - x}

x = - \frac{1}{8}

Decimal Notation

x = - 0.125

Solution steps

8^{2 x + 1} = 4^{1 - x}

Apply exponent rules

3 (2 x + 1) = 2 (1 - x)

Solve

3 (2 x + 1) = 2 (1 - x) : x = - \frac{1}{8}

x = - \frac{1}{8}

e^{x^{2} + 2} = 57

9^{x} = 2 7^{2 - 2 x}

e^{x - 1} = e^{2 (x + 1)}

4^{x - 1} + 2^{x + 2} = 48

(\frac{1}{2})^{3 a} = 2^{3 a + 3}

What is the answer to 8^{2x+1}=4^{1-x} ?
The answer to 8^{2x+1}=4^{1-x} is x=-1/8
Solve for x: 8^{2x+1}=4^{1-x}
The solution is x=-1/8