What is the answer to 2^{x-2}= 8/(2^{x-3)} ?

The answer to 2^{x-2}= 8/(2^{x-3)} is x=4

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2^{x-2}= 8/(2^{x-3)}

2^{x - 2} = \frac{8}{2 ^{x - 3}}

x = 4

Solution steps

2^{x - 2} = \frac{8}{2 ^{x - 3}}

Apply exponent rules

x - 2 = - x + 6

Solve

x - 2 = - x + 6 : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

5^{2 x} - 6 \cdot 5^{x} + 5 = 0

(\frac{1}{2})^{x} = 16

3^{- 2 x + 1} = 27

e^{2 x} = 7

6^{2 x} - 7 \cdot 6^{x} + 6 = 0

What is the answer to 2^{x-2}= 8/(2^{x-3)} ?
The answer to 2^{x-2}= 8/(2^{x-3)} is x=4
Solve for x: 2^{x-2}= 8/(2^{x-3)}
The solution is x=4