What is the answer to 4^{x^2-6}-16^{x+1}=0 ?

The answer to 4^{x^2-6}-16^{x+1}=0 is x=4,x=-2

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4^{x^2-6}-16^{x+1}=0

4^{x^{2} - 6} - 1 6^{x + 1} = 0

x = 4, x = - 2

Solution steps

4^{x^{2} - 6} - 1 6^{x + 1} = 0

Add

1 6^{x + 1}

to both sides

4^{x^{2} - 6} - 1 6^{x + 1} + 1 6^{x + 1} = 0 + 1 6^{x + 1}

Simplify

4^{x^{2} - 6} = 1 6^{x + 1}

Apply exponent rules

x^{2} - 6 = 2 (x + 1)

Solve

x^{2} - 6 = 2 (x + 1) : x = 4, x = - 2

x = 4, x = - 2

x, e^{9 x} - 5 e^{3 x} + 4 = 0

2^{2 x + 1} - 9 \cdot 2^{x} + 4 = 0

4^{2 x - 5} = 64

e^{2 x} - 5 e^{x} - 6 = 0

5^{x} = 6

What is the answer to 4^{x^2-6}-16^{x+1}=0 ?
The answer to 4^{x^2-6}-16^{x+1}=0 is x=4,x=-2
Solve for x: 4^{x^2-6}-16^{x+1}=0
The solution is x=4,x=-2