What is the answer to (1/2)^{x+2}=16^{-x} ?

The answer to (1/2)^{x+2}=16^{-x} is x= 2/3

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(1/2)^{x+2}=16^{-x}

(\frac{1}{2})^{x + 2} = 1 6^{- x}

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

(\frac{1}{2})^{x + 2} = 1 6^{- x}

Apply exponent rules

- (x + 2) = - 4 x

Solve

- (x + 2) = - 4 x : x = \frac{2}{3}

x = \frac{2}{3}

e^{x} = x + 2

\frac{7 ^{7}}{7 ^{3}} = 7^{x}

5^{- x} = 125

3 = e^{x}

2^{x} = 65536

What is the answer to (1/2)^{x+2}=16^{-x} ?
The answer to (1/2)^{x+2}=16^{-x} is x= 2/3
Solve for x: (1/2)^{x+2}=16^{-x}
The solution is x= 2/3