What is the answer to 9^{3x+2}= 1/(3^{2x-5)} ?

The answer to 9^{3x+2}= 1/(3^{2x-5)} is x= 1/8

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9^{3x+2}= 1/(3^{2x-5)}

9^{3 x + 2} = \frac{1}{3 ^{2 x - 5}}

x = \frac{1}{8}

Solution steps

9^{3 x + 2} = \frac{1}{3 ^{2 x - 5}}

Apply exponent rules

2 (3 x + 2) = - 2 x + 5

Solve

2 (3 x + 2) = - 2 x + 5 : x = \frac{1}{8}

x = \frac{1}{8}

Verify Solutions:

x = \frac{1}{8}

True

The solution is

x = \frac{1}{8}

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5^{2 - x} = \frac{1}{25}

3^{2 x + 1} \cdot 3^{x} = 243

6^{5} = 6^{x} \cdot 6^{4}

8 1^{2 p + 3} \cdot 27 = \frac{1}{27}

What is the answer to 9^{3x+2}= 1/(3^{2x-5)} ?
The answer to 9^{3x+2}= 1/(3^{2x-5)} is x= 1/8
Solve for x: 9^{3x+2}= 1/(3^{2x-5)}
The solution is x= 1/8