What is the answer to 7^x=3^{x+4} ?

The answer to 7^x=3^{x+4} is x=(4ln(3))/(ln(7)-ln(3))

Solve for x: 7^x=3^{x+4}

The solution is x=(4ln(3))/(ln(7)-ln(3))

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7^{x} = 3^{x + 4}

x = \frac{4 ln ( 3 )}{ln ( 7 ) - ln ( 3 )}

Decimal Notation

x = 5.18642 \dots

Solution steps

7^{x} = 3^{x + 4}

Apply exponent rules

x ln (7) = (x + 4) ln (3)

Solve

x ln (7) = (x + 4) ln (3) : x = \frac{4 ln ( 3 )}{ln ( 7 ) - ln ( 3 )}

x = \frac{4 ln ( 3 )}{ln ( 7 ) - ln ( 3 )}

4 e^{x} = 100

x, y^{x} = x^{y}

e^{2 x} = 2 e^{x}

x, 2^{x} + 2^{y} = 18

What is the answer to 7^x=3^{x+4} ?
The answer to 7^x=3^{x+4} is x=(4ln(3))/(ln(7)-ln(3))
Solve for x: 7^x=3^{x+4}
The solution is x=(4ln(3))/(ln(7)-ln(3))