What is the answer to 0.2^{x+1}=sqrt(125) ?

The answer to 0.2^{x+1}=sqrt(125) is x=-5/2

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0.2^{x+1}=sqrt(125)

0. 2^{x + 1} = 125

x = - \frac{5}{2}

Decimal Notation

x = - 2.5

Solution steps

0. 2^{x + 1} = 125

Apply exponent rules

- (x + 1) = \frac{3}{2}

Solve

- (x + 1) = \frac{3}{2} : x = - \frac{5}{2}

x = - \frac{5}{2}

7. 5^{3 r} = 2.6

4^{x} - 3 \cdot 2^{x} + 2 = 0

e^{x} + 1 = 6 e^{- x}

3 + 4 e^{x + 1} = 11

What is the answer to 0.2^{x+1}=sqrt(125) ?
The answer to 0.2^{x+1}=sqrt(125) is x=-5/2
Solve for x: 0.2^{x+1}=sqrt(125)
The solution is x=-5/2