What is the answer to 5^{x+1}=3^{2x} ?

The answer to 5^{x+1}=3^{2x} is x=(ln(5))/(2ln(3)-ln(5))

Solve for x: 5^{x+1}=3^{2x}

The solution is x=(ln(5))/(2ln(3)-ln(5))

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5^{x + 1} = 3^{2 x}

x = \frac{ln ( 5 )}{2 ln ( 3 ) - ln ( 5 )}

Decimal Notation

x = 2.73813 \dots

Solution steps

5^{x + 1} = 3^{2 x}

Apply exponent rules

(x + 1) ln (5) = 2 x ln (3)

Solve

(x + 1) ln (5) = 2 x ln (3) : x = \frac{ln ( 5 )}{2 ln ( 3 ) - ln ( 5 )}

x = \frac{ln ( 5 )}{2 ln ( 3 ) - ln ( 5 )}

4^{x + 1} - 32 = 0

1 2^{x - 1} = 1500

2 \cdot 2^{x} + 4^{x} = 80

e^{x} = \frac{4}{x}

8^{y} = 1 6^{y + 2}

What is the answer to 5^{x+1}=3^{2x} ?
The answer to 5^{x+1}=3^{2x} is x=(ln(5))/(2ln(3)-ln(5))
Solve for x: 5^{x+1}=3^{2x}
The solution is x=(ln(5))/(2ln(3)-ln(5))