What is the answer to 2^{3x+5}=64^{x-7} ?

The answer to 2^{3x+5}=64^{x-7} is x= 47/3

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2^{3x+5}=64^{x-7}

2^{3 x + 5} = 6 4^{x - 7}

x = \frac{47}{3}

Decimal Notation

x = 15.66666 \dots

Solution steps

2^{3 x + 5} = 6 4^{x - 7}

Apply exponent rules

3 x + 5 = 6 (x - 7)

Solve

3 x + 5 = 6 (x - 7) : x = \frac{47}{3}

x = \frac{47}{3}

e^{2 x} - 8 e^{x} + 15 = 0

200 = 100 e^{r \cdot 6}

2^{x} = 24

x^{x} = x^{x}

4^{2 x} - 4^{x} - 12 = 0

What is the answer to 2^{3x+5}=64^{x-7} ?
The answer to 2^{3x+5}=64^{x-7} is x= 47/3
Solve for x: 2^{3x+5}=64^{x-7}
The solution is x= 47/3