What is the answer to 3^{x-1}=4 ?

The answer to 3^{x-1}=4 is x=(2ln(2))/(ln(3))+1

Solve for x: 3^{x-1}=4

The solution is x=(2ln(2))/(ln(3))+1

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3^{x - 1} = 4

x = \frac{2 ln ( 2 )}{ln ( 3 )} + 1

Decimal Notation

x = 2.26185 \dots

Solution steps

3^{x - 1} = 4

Apply exponent rules

(x - 1) ln (3) = ln (4)

Solve

(x - 1) ln (3) = ln (4) : x = \frac{2 ln ( 2 )}{ln ( 3 )} + 1

x = \frac{2 ln ( 2 )}{ln ( 3 )} + 1

2^{x + 4} = e^{3 x}

100 0^{x} = 1000000

5 \cdot 6^{- 2 x - 1} - 1 = 7

2^{4 x} (3 2^{1 - x}) = 8^{x + 2}

What is the answer to 3^{x-1}=4 ?
The answer to 3^{x-1}=4 is x=(2ln(2))/(ln(3))+1
Solve for x: 3^{x-1}=4
The solution is x=(2ln(2))/(ln(3))+1