What is the answer to 5(1.2)^{x-1}=4 ?

The answer to 5(1.2)^{x-1}=4 is x=(ln(4/5))/(ln(1.2))+1

Solve for x: 5(1.2)^{x-1}=4

The solution is x=(ln(4/5))/(ln(1.2))+1

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5 (1.2)^{x - 1} = 4

x = \frac{ln ( \frac{4}{5} )}{ln ( 1.2 )} + 1

Decimal Notation

x = - 0.22390 \dots

Solution steps

5 (1.2)^{x - 1} = 4

Divide both sides by

5

1. 2^{x - 1} = \frac{4}{5}

Apply exponent rules

(x - 1) ln (1.2) = ln (\frac{4}{5})

Solve

(x - 1) ln (1.2) = ln (\frac{4}{5}) : x = \frac{ln ( \frac{4}{5} )}{ln ( 1.2 )} + 1

x = \frac{ln ( \frac{4}{5} )}{ln ( 1.2 )} + 1

(\frac{625}{256})^{5 x - 4} = 1

16 = 4^{x}

3 e^{2 x} = 9

5^{3 x - 1} = 49

1 0^{\frac{4}{x}} = 6

What is the answer to 5(1.2)^{x-1}=4 ?
The answer to 5(1.2)^{x-1}=4 is x=(ln(4/5))/(ln(1.2))+1
Solve for x: 5(1.2)^{x-1}=4
The solution is x=(ln(4/5))/(ln(1.2))+1