What is the answer to solvefor w,x^{72}+x^w=x^8 ?

The answer to solvefor w,x^{72}+x^w=x^8 is w=(ln(x^8-x^{72}))/(ln(x))

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solvefor w,x^{72}+x^w=x^8

solve for

w, x^{72} + x^{w} = x^{8}

w = \frac{ln ( x ^{8} - x ^{72} )}{ln ( x )}

Solution steps

x^{72} + x^{w} = x^{8}

Move

x^{72}

to the right side

x^{w} = x^{8} - x^{72}

Apply exponent rules

w ln (x) = ln (x^{8} - x^{72})

Solve

w ln (x) = ln (x^{8} - x^{72}) : w = \frac{ln ( x ^{8} - x ^{72} )}{ln ( x )}

w = \frac{ln ( x ^{8} - x ^{72} )}{ln ( x )}

7^{x} = 8

8^{x} = 512

8 e^{2 x} - 43 e^{x} - 30 = 0

7 \cdot 3^{x} = 189

(5^{x})^{2} + 8 = 12 5^{2} x

What is the answer to solvefor w,x^{72}+x^w=x^8 ?
The answer to solvefor w,x^{72}+x^w=x^8 is w=(ln(x^8-x^{72}))/(ln(x))