What is the answer to 7^{3-5x}=(1/49)^{2x+9} ?

The answer to 7^{3-5x}=(1/49)^{2x+9} is x=21

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7^{3-5x}=(1/49)^{2x+9}

7^{3 - 5 x} = (\frac{1}{49})^{2 x + 9}

x = 21

Solution steps

7^{3 - 5 x} = (\frac{1}{49})^{2 x + 9}

Apply exponent rules

3 - 5 x = - 2 (2 x + 9)

Solve

3 - 5 x = - 2 (2 x + 9) : x = 21

x = 21

9^{x} = \frac{1}{27}

- 3 \cdot e^{5 w} = - 88

3^{x} = 2^{x + 1}

2^{x + 1} = 64

e^{x} - 6 e^{- x} = 1

What is the answer to 7^{3-5x}=(1/49)^{2x+9} ?
The answer to 7^{3-5x}=(1/49)^{2x+9} is x=21
Solve for x: 7^{3-5x}=(1/49)^{2x+9}
The solution is x=21