What is the answer to solvefor x,e^x+e^{-x}=3 ?

The answer to solvefor x,e^x+e^{-x}=3 is x=ln((3+sqrt(5))/2),x=ln((3-sqrt(5))/2)

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solvefor x,e^x+e^{-x}=3

solve for

x, e^{x} + e^{- x} = 3

x = ln (\frac{3 + 5}{2}), x = ln (\frac{3 - 5}{2})

Solution steps

e^{x} + e^{- x} = 3

Apply exponent rules

e^{x} + (e^{x})^{- 1} = 3

Rewrite the equation with

e^{x} = u

u + (u)^{- 1} = 3

Solve

u + u^{- 1} = 3 : u = \frac{3 + 5}{2}, u = \frac{3 - 5}{2}

u = \frac{3 + 5}{2}, u = \frac{3 - 5}{2}

Substitute back

u = e^{x},

solve for

x

Solve

e^{x} = \frac{3 + 5}{2} : x = ln (\frac{3 + 5}{2})

Solve

e^{x} = \frac{3 - 5}{2} : x = ln (\frac{3 - 5}{2})

x = ln (\frac{3 + 5}{2}), x = ln (\frac{3 - 5}{2})

k, n = 2^{k}

3^{x} = 19

9^{b^{3} - 1} = 81

e^{4.2 x} = 69

2 5^{x} = 5

What is the answer to solvefor x,e^x+e^{-x}=3 ?
The answer to solvefor x,e^x+e^{-x}=3 is x=ln((3+sqrt(5))/2),x=ln((3-sqrt(5))/2)