What is the answer to 5^{4x+1}=4^{3x+2} ?

The answer to 5^{4x+1}=4^{3x+2} is x=(4ln(2)-ln(5))/(2(2ln(5)-3ln(2)))

Solve for x: 5^{4x+1}=4^{3x+2}

The solution is x=(4ln(2)-ln(5))/(2(2ln(5)-3ln(2)))

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5^{4 x + 1} = 4^{3 x + 2}

x = \frac{4 ln ( 2 ) - ln ( 5 )}{2 ( 2 ln ( 5 ) - 3 ln ( 2 ) )}

Decimal Notation

x = 0.51040 \dots

Solution steps

5^{4 x + 1} = 4^{3 x + 2}

Apply exponent rules

(4 x + 1) ln (5) = (3 x + 2) ln (4)

Solve

(4 x + 1) ln (5) = (3 x + 2) ln (4) : x = \frac{4 ln ( 2 ) - ln ( 5 )}{2 ( 2 ln ( 5 ) - 3 ln ( 2 ) )}

x = \frac{4 ln ( 2 ) - ln ( 5 )}{2 ( 2 ln ( 5 ) - 3 ln ( 2 ) )}

x, 8^{x} = 3

- e^{x} = 0

9^{x} = 3^{x} + 6

3^{x^{2} - 5} = 81

10 0^{3 x - 3} = 1 0^{4 x - 9}

What is the answer to 5^{4x+1}=4^{3x+2} ?
The answer to 5^{4x+1}=4^{3x+2} is x=(4ln(2)-ln(5))/(2(2ln(5)-3ln(2)))
Solve for x: 5^{4x+1}=4^{3x+2}
The solution is x=(4ln(2)-ln(5))/(2(2ln(5)-3ln(2)))