What is the answer to 4^{2x}=3^{x+1} ?

The answer to 4^{2x}=3^{x+1} is x=(ln(3))/(4ln(2)-ln(3))

Solve for x: 4^{2x}=3^{x+1}

The solution is x=(ln(3))/(4ln(2)-ln(3))

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4^{2 x} = 3^{x + 1}

x = \frac{ln ( 3 )}{4 ln ( 2 ) - ln ( 3 )}

Decimal Notation

x = 0.65628 \dots

Solution steps

4^{2 x} = 3^{x + 1}

Apply exponent rules

2 x ln (4) = (x + 1) ln (3)

Solve

2 x ln (4) = (x + 1) ln (3) : x = \frac{ln ( 3 )}{4 ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( 3 )}{4 ln ( 2 ) - ln ( 3 )}

4^{x} = 512

e^{y} = 2

e^{y} = 5

e^{y} = 3

3^{x + 2} = 3^{x} + 3^{2}

What is the answer to 4^{2x}=3^{x+1} ?
The answer to 4^{2x}=3^{x+1} is x=(ln(3))/(4ln(2)-ln(3))
Solve for x: 4^{2x}=3^{x+1}
The solution is x=(ln(3))/(4ln(2)-ln(3))