What is the answer to 4*10^{-3x}=18 ?

The answer to 4*10^{-3x}=18 is x=-(ln(9/2))/(3ln(10))

Solve for x: 4*10^{-3x}=18

The solution is x=-(ln(9/2))/(3ln(10))

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4 \cdot 1 0^{- 3 x} = 18

x = - \frac{ln ( \frac{9}{2} )}{3 ln ( 10 )}

Solution steps

4 \cdot 1 0^{- 3 x} = 18

Divide both sides by

4

1 0^{- 3 x} = \frac{9}{2}

Apply exponent rules

- 3 x ln (10) = ln (\frac{9}{2})

Solve

- 3 x ln (10) = ln (\frac{9}{2}) : x = - \frac{ln ( \frac{9}{2} )}{3 ln ( 10 )}

x = - \frac{ln ( \frac{9}{2} )}{3 ln ( 10 )}

2^{x - 1} = 16

3^{x^{2} - 3 x} = 81

1 6^{2 p} = 3 2^{p + 3}

2^{3 x + 1} = 128

5 ln (7 - e^{2 x}) = 3

What is the answer to 4*10^{-3x}=18 ?
The answer to 4*10^{-3x}=18 is x=-(ln(9/2))/(3ln(10))
Solve for x: 4*10^{-3x}=18
The solution is x=-(ln(9/2))/(3ln(10))