What is the answer to 2^{2x}+4^{x-1}+44=2^{2x+2} ?

The answer to 2^{2x}+4^{x-1}+44=2^{2x+2} is x=2

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2^{2x}+4^{x-1}+44=2^{2x+2}

2^{2 x} + 4^{x - 1} + 44 = 2^{2 x + 2}

x = 2

Solution steps

2^{2 x} + 4^{x - 1} + 44 = 2^{2 x + 2}

Apply exponent rules

2 x = 4

Solve

2 x = 4 : x = 2

x = 2

7^{3 x - 2} = 11

4^{x} = 11

4^{x} = 10

6 4^{x} = 51 2^{x - 5}

b^{x - 1} \cdot b^{x + 1} = b^{8}

What is the answer to 2^{2x}+4^{x-1}+44=2^{2x+2} ?
The answer to 2^{2x}+4^{x-1}+44=2^{2x+2} is x=2
Solve for x: 2^{2x}+4^{x-1}+44=2^{2x+2}
The solution is x=2