What is the answer to 4^{(2z)/3}=8^{(z+2)} ?

The answer to 4^{(2z)/3}=8^{(z+2)} is z=-18/5

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4^{(2z)/3}=8^{(z+2)}

4^{\frac{2 z}{3}} = 8^{(z + 2)}

z = - \frac{18}{5}

Solution steps

4^{\frac{2 z}{3}} = 8^{(z + 2)}

Apply exponent rules

\frac{4 z}{3} = 3 (z + 2)

Solve

\frac{4 z}{3} = 3 (z + 2) : z = - \frac{18}{5}

z = - \frac{18}{5}

9^{x} = 3

8 1^{3^{2 x}} = 2 7^{4^{2 x}}

9^{2 x} = 27

2^{2 x - 1} - 6 \cdot 2^{x - 1} + 4 = 0

3 2^{x} = 2

What is the answer to 4^{(2z)/3}=8^{(z+2)} ?
The answer to 4^{(2z)/3}=8^{(z+2)} is z=-18/5
Solve for z: 4^{(2z)/3}=8^{(z+2)}
The solution is z=-18/5