What is the answer to 10^{1-x}=6^x ?

The answer to 10^{1-x}=6^x is x=(ln(10))/(ln(60))

Solve for x: 10^{1-x}=6^x

The solution is x=(ln(10))/(ln(60))

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1 0^{1 - x} = 6^{x}

x = \frac{ln ( 10 )}{ln ( 60 )}

Decimal Notation

x = 0.56238 \dots

Solution steps

1 0^{1 - x} = 6^{x}

Apply exponent rules

(1 - x) ln (10) = x ln (6)

Solve

(1 - x) ln (10) = x ln (6) : x = \frac{ln ( 10 )}{ln ( 60 )}

x = \frac{ln ( 10 )}{ln ( 60 )}

2433 = 3^{a}

e^{2 x} + e^{x} - 9 = 0

8 1^{x} = 64

x, e^{6 x} - 5 e^{3 x} + 4 = 0

14 4^{2 x + 1} = 1 2^{5 x - 1}

What is the answer to 10^{1-x}=6^x ?
The answer to 10^{1-x}=6^x is x=(ln(10))/(ln(60))
Solve for x: 10^{1-x}=6^x
The solution is x=(ln(10))/(ln(60))