What is the answer to (-e^{-k}+e^{(-5k)/6})=2 ?

The answer to (-e^{-k}+e^{(-5k)/6})=2 is No Solution for k\in\mathbb{R}

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(-e^{-k}+e^{(-5k)/6})=2

(- e^{- k} + e^{\frac{- 5 k}{6}}) = 2

No Solution for k \in R

Solution steps

(- e^{- k} + e^{\frac{- 5 k}{6}}) = 2

Apply exponent rules

- (e^{k})^{- 1} + (e^{k})^{- 0.83333 \dots} = 2

Rewrite the equation with

e^{k} = u

- (u)^{- 1} + (u)^{- 0.83333 \dots} = 2

Solve

- u^{- 1} + u^{- 0.83333 \dots} = 2 :

No Solution for

u \in R

No Solution for k \in R

2^{2 x} = 16

(e^{4})^{x} e^{x^{2}} = e^{12}

6^{x} = 5

k, \frac{n}{2 ^{k}} = 1

t, e^{k t} = \frac{1}{2}

What is the answer to (-e^{-k}+e^{(-5k)/6})=2 ?
The answer to (-e^{-k}+e^{(-5k)/6})=2 is No Solution for k\in\mathbb{R}