What are the solutions to the equation 3x^2+x-1=0 ?

The solutions to the equation 3x^2+x-1=0 are x=(-1+sqrt(13))/6 ,x=(-1-sqrt(13))/6

Find the zeros of 3x^2+x-1=0

The zeros of 3x^2+x-1=0 are x=(-1+sqrt(13))/6 ,x=(-1-sqrt(13))/6

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3 x^{2} + x - 1 = 0

x = \frac{- 1 + 13}{6}, x = \frac{- 1 - 13}{6}

Solution steps

3 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 1) = 13

x_{1, 2} = \frac{- 1 \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 13}{2 \cdot 3}, x_{2} = \frac{- 1 - 13}{2 \cdot 3}

x = \frac{- 1 + 13}{2 \cdot 3} : \frac{- 1 + 13}{6}

x = \frac{- 1 - 13}{2 \cdot 3} : \frac{- 1 - 13}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 13}{6}, x = \frac{- 1 - 13}{6}

5 x^{2} - 25 = 0

\frac{x}{2} - \frac{1}{2} \leq \frac{x}{3} + 1

\frac{\frac{2}{3}}{\frac{4}{5}}

2 y^{2} - 13 y + 18

9 m^{2} - 30 m

What are the solutions to the equation 3x^2+x-1=0 ?
The solutions to the equation 3x^2+x-1=0 are x=(-1+sqrt(13))/6 ,x=(-1-sqrt(13))/6
Find the zeros of 3x^2+x-1=0
The zeros of 3x^2+x-1=0 are x=(-1+sqrt(13))/6 ,x=(-1-sqrt(13))/6