What is the answer to log_{3}(3^{2x+1})=15 ?

The answer to log_{3}(3^{2x+1})=15 is x=7

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log_{3}(3^{2x+1})=15

lo g_{3} (3^{2 x + 1}) = 15

x = 7

Solution steps

lo g_{3} (3^{2 x + 1}) = 15

Apply exponent rules

2 x + 1 = 15

Solve

2 x + 1 = 15 : x = 7

x = 7

1 6^{3^{2 x}} = 8^{4^{2 x}}

6^{x} = 36

2^{n} = 3600000

6^{3 x + 4} = \frac{1}{36}

3^{x + 1} = 2

What is the answer to log_{3}(3^{2x+1})=15 ?
The answer to log_{3}(3^{2x+1})=15 is x=7
Solve for x: log_{3}(3^{2x+1})=15
The solution is x=7