What is the answer to 3^{x+2}=5^{x-1} ?

The answer to 3^{x+2}=5^{x-1} is x=(ln(45))/(ln(5)-ln(3))

Solve for x: 3^{x+2}=5^{x-1}

The solution is x=(ln(45))/(ln(5)-ln(3))

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3^{x + 2} = 5^{x - 1}

x = \frac{ln ( 45 )}{ln ( 5 ) - ln ( 3 )}

Decimal Notation

x = 7.45198 \dots

Solution steps

3^{x + 2} = 5^{x - 1}

Apply exponent rules

(x + 2) ln (3) = (x - 1) ln (5)

Solve

(x + 2) ln (3) = (x - 1) ln (5) : x = \frac{ln ( 45 )}{ln ( 5 ) - ln ( 3 )}

x = \frac{ln ( 45 )}{ln ( 5 ) - ln ( 3 )}

x^{3} = 3^{x}

e^{l n (x)} = 4

5^{x + 3} \cdot 5^{2 x - 4} = 125

2 \cdot 3^{4 t} = 5^{- t}

4^{x + 2} = 64

What is the answer to 3^{x+2}=5^{x-1} ?
The answer to 3^{x+2}=5^{x-1} is x=(ln(45))/(ln(5)-ln(3))
Solve for x: 3^{x+2}=5^{x-1}
The solution is x=(ln(45))/(ln(5)-ln(3))