What is the answer to 12^{x^2+5x-4}=12^{2x+6} ?

The answer to 12^{x^2+5x-4}=12^{2x+6} is x=2,x=-5

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12^{x^2+5x-4}=12^{2x+6}

1 2^{x^{2} + 5 x - 4} = 1 2^{2 x + 6}

x = 2, x = - 5

Solution steps

1 2^{x^{2} + 5 x - 4} = 1 2^{2 x + 6}

Apply exponent rules

x^{2} + 5 x - 4 = 2 x + 6

Solve

x^{2} + 5 x - 4 = 2 x + 6 : x = 2, x = - 5

x = 2, x = - 5

2 7^{x^{4}} = 9^{24}

\frac{1 0 ^{x} + 1}{1 + 1 0 ^{- x}} = 100

2 e^{2 x} = 0

3^{2 x} = 3^{6}

4^{x} - 6 (2^{x}) = - 8

What is the answer to 12^{x^2+5x-4}=12^{2x+6} ?
The answer to 12^{x^2+5x-4}=12^{2x+6} is x=2,x=-5
Solve for x: 12^{x^2+5x-4}=12^{2x+6}
The solution is x=2,x=-5