What are the solutions to the equation (3x-2)^2=39 ?

The solutions to the equation (3x-2)^2=39 are x=(sqrt(39)+2)/3 ,x=(-sqrt(39)+2)/3

Find the zeros of (3x-2)^2=39

The zeros of (3x-2)^2=39 are x=(sqrt(39)+2)/3 ,x=(-sqrt(39)+2)/3

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(3 x - 2)^{2} = 39

x = \frac{39 + 2}{3}, x = \frac{- 39 + 2}{3}

Solution steps

(3 x - 2)^{2} = 39

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 2 = 39 : x = \frac{39 + 2}{3}

Solve

3 x - 2 = - 39 : x = \frac{- 39 + 2}{3}

The solutions to the quadratic equation are:

x = \frac{39 + 2}{3}, x = \frac{- 39 + 2}{3}

8 x^{2} - 17 x - 21

3 ∣ x - 1 ∣ = ∣ - 2 x - 2 ∣ + 4

(\frac{1}{32})^{\frac{1}{5}}

\frac{( 3 - 5 i )}{( 2 - 5 i )}

x + 1 x - 1

What are the solutions to the equation (3x-2)^2=39 ?
The solutions to the equation (3x-2)^2=39 are x=(sqrt(39)+2)/3 ,x=(-sqrt(39)+2)/3
Find the zeros of (3x-2)^2=39
The zeros of (3x-2)^2=39 are x=(sqrt(39)+2)/3 ,x=(-sqrt(39)+2)/3