What is the answer to 3^{2(x+1)}-28*3^x+3=0 ?

The answer to 3^{2(x+1)}-28*3^x+3=0 is x=1,x=-2

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3^{2(x+1)}-28*3^x+3=0

3^{2 (x + 1)} - 28 \cdot 3^{x} + 3 = 0

x = 1, x = - 2

Solution steps

3^{2 (x + 1)} - 28 \cdot 3^{x} + 3 = 0

Apply exponent rules

(3^{x})^{2} \cdot 3^{2} - 28 \cdot 3^{x} + 3 = 0

Rewrite the equation with

3^{x} = u

(u)^{2} \cdot 3^{2} - 28 u + 3 = 0

Solve

u^{2} \cdot 3^{2} - 28 u + 3 = 0 : u = 3, u = \frac{1}{9}

u = 3, u = \frac{1}{9}

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 3 : x = 1

Solve

3^{x} = \frac{1}{9} : x = - 2

x = 1, x = - 2

e^{- x} - e^{- x} x = 0

7^{x} = 21

\frac{1}{4} = 2^{x}

2^{b} = 16

4^{x} = 20

What is the answer to 3^{2(x+1)}-28*3^x+3=0 ?
The answer to 3^{2(x+1)}-28*3^x+3=0 is x=1,x=-2
Solve for x: 3^{2(x+1)}-28*3^x+3=0
The solution is x=1,x=-2