What is the answer to 2^{2x+3}=3^{3x} ?

The answer to 2^{2x+3}=3^{3x} is x=(3ln(2))/(3ln(3)-2ln(2))

Solve for x: 2^{2x+3}=3^{3x}

The solution is x=(3ln(2))/(3ln(3)-2ln(2))

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2^{2 x + 3} = 3^{3 x}

x = \frac{3 ln ( 2 )}{3 ln ( 3 ) - 2 ln ( 2 )}

Solution steps

2^{2 x + 3} = 3^{3 x}

Apply exponent rules

(2 x + 3) ln (2) = 3 x ln (3)

Solve

(2 x + 3) ln (2) = 3 x ln (3) : x = \frac{3 ln ( 2 )}{3 ln ( 3 ) - 2 ln ( 2 )}

x = \frac{3 ln ( 2 )}{3 ln ( 3 ) - 2 ln ( 2 )}

5^{x} - 75 \cdot 5^{- x} = 22

1.0 4^{x} = 2

5^{x} = 5^{3} \cdot 5^{8}

- 6 \cdot 2^{0.1 x} = - 100

5^{x} = 26

What is the answer to 2^{2x+3}=3^{3x} ?
The answer to 2^{2x+3}=3^{3x} is x=(3ln(2))/(3ln(3)-2ln(2))
Solve for x: 2^{2x+3}=3^{3x}
The solution is x=(3ln(2))/(3ln(3)-2ln(2))