What is the answer to 73=23^x ?

The answer to 73=23^x is x=(ln(73))/(ln(23))

The solution is x=(ln(73))/(ln(23))

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73=23^x

73 = 2 3^{x}

x = \frac{ln ( 73 )}{ln ( 23 )}

Solution steps

73 = 2 3^{x}

Apply exponent rules

ln (73) = x ln (23)

Solve

ln (73) = x ln (23) : x = \frac{ln ( 73 )}{ln ( 23 )}

x = \frac{ln ( 73 )}{ln ( 23 )}

9^{x + 1} + 3 = 28 \cdot 3^{x}

4 9^{x} = 7

1 0^{x} + 5 = 60

e^{x - 1} - 5 = 5

e^{x} = 20