What is the answer to 16^{2x}=8^{x-1} ?

The answer to 16^{2x}=8^{x-1} is x=-3/5

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16^{2x}=8^{x-1}

1 6^{2 x} = 8^{x - 1}

x = - \frac{3}{5}

Decimal Notation

x = - 0.6

Solution steps

1 6^{2 x} = 8^{x - 1}

Apply exponent rules

8 x = 3 (x - 1)

Solve

8 x = 3 (x - 1) : x = - \frac{3}{5}

x = - \frac{3}{5}

100 = \frac{300}{1 + e ^{4 - t}}

8^{x} = 4^{x + 1}

6^{2 x - 6} = 3 6^{3 x - 5}

2^{x} - x^{2} = 0

(0.5)^{\frac{9900}{x}} = 0.3