What is the answer to 3^{4-x^2}= 1/9 ?

The answer to 3^{4-x^2}= 1/9 is x=sqrt(6),x=-sqrt(6)

Solve for x: 3^{4-x^2}= 1/9

The solution is x=sqrt(6),x=-sqrt(6)

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3^{4 - x^{2}} = \frac{1}{9}

x = 6, x = - 6

Solution steps

3^{4 - x^{2}} = \frac{1}{9}

Apply exponent rules

4 - x^{2} = - 2

Solve

4 - x^{2} = - 2 : x = 6, x = - 6

x = 6, x = - 6

2 e^{x} = 1

2^{- m} = 2^{3 m - 3}

5^{2 x} - 6 (5^{x}) + 5 = 0

5^{2 x + 7} = 2 5^{\frac{1}{3}}

4^{- 2 x + 6} = \frac{1}{8}

What is the answer to 3^{4-x^2}= 1/9 ?
The answer to 3^{4-x^2}= 1/9 is x=sqrt(6),x=-sqrt(6)
Solve for x: 3^{4-x^2}= 1/9
The solution is x=sqrt(6),x=-sqrt(6)