What is the answer to 6^{2x}=3*2^x ?

The answer to 6^{2x}=3*2^x is x=(ln(3))/(ln(18))

Solve for x: 6^{2x}=3*2^x

The solution is x=(ln(3))/(ln(18))

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6^{2 x} = 3 \cdot 2^{x}

x = \frac{ln ( 3 )}{ln ( 18 )}

Decimal Notation

x = 0.38009 \dots

Solution steps

6^{2 x} = 3 \cdot 2^{x}

Apply exponent rules

2 x ln (6) = ln (3) + x ln (2)

Solve

2 x ln (6) = ln (3) + x ln (2) : x = \frac{ln ( 3 )}{ln ( 18 )}

x = \frac{ln ( 3 )}{ln ( 18 )}

x, 2^{x} = 5

9^{x + 4} = 2 7^{x}

2 5^{x + 2} = 5^{3 x - 4}

2^{x + 1} = 1 0^{- x}

e^{- 9 x} = 3

What is the answer to 6^{2x}=3*2^x ?
The answer to 6^{2x}=3*2^x is x=(ln(3))/(ln(18))
Solve for x: 6^{2x}=3*2^x
The solution is x=(ln(3))/(ln(18))