What are the solutions to the equation 3x^2+10x=4 ?

The solutions to the equation 3x^2+10x=4 are x=(-5+sqrt(37))/3 ,x=-(5+sqrt(37))/3

Find the zeros of 3x^2+10x=4

The zeros of 3x^2+10x=4 are x=(-5+sqrt(37))/3 ,x=-(5+sqrt(37))/3

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3 x^{2} + 10 x = 4

x = \frac{- 5 + 37}{3}, x = - \frac{5 + 37}{3}

Decimal Notation

x = 0.36092 \dots, x = - 3.69425 \dots

Solution steps

3 x^{2} + 10 x = 4

Move

4

to the left side

3 x^{2} + 10 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 4) = 237

x_{1, 2} = \frac{- 10 \pm 2 37}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 2 37}{2 \cdot 3}, x_{2} = \frac{- 10 - 2 37}{2 \cdot 3}

x = \frac{- 10 + 2 37}{2 \cdot 3} : \frac{- 5 + 37}{3}

x = \frac{- 10 - 2 37}{2 \cdot 3} : - \frac{5 + 37}{3}

The solutions to the quadratic equation are:

x = \frac{- 5 + 37}{3}, x = - \frac{5 + 37}{3}

\frac{13 !}{5 ! ( 13 - 5 ) !}

- \frac{20}{20}

\frac{x + 5}{x + 3} \geq 0

(x - 3) (x - 5) = 35

s^{2} + 5 s + 4

What are the solutions to the equation 3x^2+10x=4 ?
The solutions to the equation 3x^2+10x=4 are x=(-5+sqrt(37))/3 ,x=-(5+sqrt(37))/3
Find the zeros of 3x^2+10x=4
The zeros of 3x^2+10x=4 are x=(-5+sqrt(37))/3 ,x=-(5+sqrt(37))/3