What is the answer to 1+e^x=0 ?

The answer to 1+e^x=0 is No Solution for x\in\mathbb{R}

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1+e^x=0

1 + e^{x} = 0

No Solution for x \in R

Solution steps

1 + e^{x} = 0

Subtract

e^{x}

from both sides

1 + e^{x} - e^{x} = 0 - e^{x}

Simplify

1 = - e^{x}

Move

e^{x}

to the left side

1 + e^{x} = 0

Move

1

to the right side

e^{x} = - 1

a^{f (x)}

cannot be zero or negative for

x \in R

No Solution for x \in R

4 \cdot e^{2.7 x} = 33

6^{x + 1} = 162 \cdot 2^{x}

lo g_{5} (2 5^{4 x - 1}) = 3

(\frac{1}{27})^{x} = \frac{1}{3}

What is the answer to 1+e^x=0 ?
The answer to 1+e^x=0 is No Solution for x\in\mathbb{R}