What is the answer to 27^{9x+4}*3^{x-8}=3^{x+9} ?

The answer to 27^{9x+4}*3^{x-8}=3^{x+9} is x= 5/27

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27^{9x+4}*3^{x-8}=3^{x+9}

2 7^{9 x + 4} \cdot 3^{x - 8} = 3^{x + 9}

x = \frac{5}{27}

Decimal Notation

x = 0.18518 \dots

Solution steps

2 7^{9 x + 4} \cdot 3^{x - 8} = 3^{x + 9}

Apply exponent rules

3 (9 x + 4) + x - 8 = x + 9

Solve

3 (9 x + 4) + x - 8 = x + 9 : x = \frac{5}{27}

x = \frac{5}{27}

2^{x} - 1 = 0

e^{2 x} = e^{x}

3^{x^{3}} = 9^{x}

2 e^{x} - e^{- 3 x} = 0

0.7 5^{x} = \frac{9}{16}

What is the answer to 27^{9x+4}*3^{x-8}=3^{x+9} ?
The answer to 27^{9x+4}*3^{x-8}=3^{x+9} is x= 5/27
Solve for x: 27^{9x+4}*3^{x-8}=3^{x+9}
The solution is x= 5/27