What is the answer to 4^{(1-x)}=3^{(2x+3)} ?

The answer to 4^{(1-x)}=3^{(2x+3)} is x=-(3ln(3)-2ln(2))/(2ln(6))

Solve for x: 4^{(1-x)}=3^{(2x+3)}

The solution is x=-(3ln(3)-2ln(2))/(2ln(6))

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4^{(1 - x)} = 3^{(2 x + 3)}

x = - \frac{3 ln ( 3 ) - 2 ln ( 2 )}{2 ln ( 6 )}

Decimal Notation

x = - 0.53286 \dots

Solution steps

4^{(1 - x)} = 3^{(2 x + 3)}

Apply exponent rules

(1 - x) ln (4) = (2 x + 3) ln (3)

Solve

(1 - x) ln (4) = (2 x + 3) ln (3) : x = - \frac{3 ln ( 3 ) - 2 ln ( 2 )}{2 ln ( 6 )}

x = - \frac{3 ln ( 3 ) - 2 ln ( 2 )}{2 ln ( 6 )}

e^{e^{e^{x}}} = 15.1546741867000 \dots

e^{x - 3} + 1 = 4 x - 3

3 e^{t} = 5 + 8 e^{- t}

8 = 3^{x}

8^{4 x + 2} = 64

What is the answer to 4^{(1-x)}=3^{(2x+3)} ?
The answer to 4^{(1-x)}=3^{(2x+3)} is x=-(3ln(3)-2ln(2))/(2ln(6))
Solve for x: 4^{(1-x)}=3^{(2x+3)}
The solution is x=-(3ln(3)-2ln(2))/(2ln(6))