What is the answer to (3^{n-2})/(9^{1-n)}=1 ?

The answer to (3^{n-2})/(9^{1-n)}=1 is n= 4/3

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(3^{n-2})/(9^{1-n)}=1

\frac{3 ^{n - 2}}{9 ^{1 - n}} = 1

n = \frac{4}{3}

Decimal Notation

n = 1.33333 \dots

Solution steps

\frac{3 ^{n - 2}}{9 ^{1 - n}} = 1

Apply exponent rules

3 (n - 2) = - 2

Solve

3 (n - 2) = - 2 : n = \frac{4}{3}

n = \frac{4}{3}

Verify Solutions:

n = \frac{4}{3}

True

The solution is

n = \frac{4}{3}

9^{x - 1} = 4^{2 x}

\frac{15}{e ^{2 x}} = 3

3^{2 x + 1} = 27

4^{2 x + 1} = 4

2^{n + 1} = 32

What is the answer to (3^{n-2})/(9^{1-n)}=1 ?
The answer to (3^{n-2})/(9^{1-n)}=1 is n= 4/3
Solve for n: (3^{n-2})/(9^{1-n)}=1
The solution is n= 4/3