What is the answer to 4^{x^2+4x}=2^{-6} ?

The answer to 4^{x^2+4x}=2^{-6} is x=-1,x=-3

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4^{x^2+4x}=2^{-6}

4^{x^{2} + 4 x} = 2^{- 6}

x = - 1, x = - 3

Solution steps

4^{x^{2} + 4 x} = 2^{- 6}

Apply exponent rules

2 (x^{2} + 4 x) = - 6

Solve

2 (x^{2} + 4 x) = - 6 : x = - 1, x = - 3

x = - 1, x = - 3

8 1^{x - 3} = (\frac{1}{9})^{2 x - 1}

\frac{1}{25} = 5^{x + 4}

7^{x - 10} = 25

8^{(x^{2} + 2 x - 15)} = 1

\frac{2 ^{x} - 2 ^{- x}}{3} = 4

What is the answer to 4^{x^2+4x}=2^{-6} ?
The answer to 4^{x^2+4x}=2^{-6} is x=-1,x=-3
Solve for x: 4^{x^2+4x}=2^{-6}
The solution is x=-1,x=-3