What is the answer to 4^{2x-1}=3^{x+2} ?

The answer to 4^{2x-1}=3^{x+2} is x=(2ln(6))/(4ln(2)-ln(3))

Solve for x: 4^{2x-1}=3^{x+2}

The solution is x=(2ln(6))/(4ln(2)-ln(3))

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4^{2 x - 1} = 3^{x + 2}

x = \frac{2 ln ( 6 )}{4 ln ( 2 ) - ln ( 3 )}

Decimal Notation

x = 2.14072 \dots

Solution steps

4^{2 x - 1} = 3^{x + 2}

Apply exponent rules

(2 x - 1) ln (4) = (x + 2) ln (3)

Solve

(2 x - 1) ln (4) = (x + 2) ln (3) : x = \frac{2 ln ( 6 )}{4 ln ( 2 ) - ln ( 3 )}

x = \frac{2 ln ( 6 )}{4 ln ( 2 ) - ln ( 3 )}

e^{x} - 7 = 2 e^{- x}

e^{x - 1} = 1

9^{x} - 12 \cdot 3^{x} + 27 = 0

2 5^{2 x} = 5

e^{- 4 x} = 3

What is the answer to 4^{2x-1}=3^{x+2} ?
The answer to 4^{2x-1}=3^{x+2} is x=(2ln(6))/(4ln(2)-ln(3))
Solve for x: 4^{2x-1}=3^{x+2}
The solution is x=(2ln(6))/(4ln(2)-ln(3))