What is the answer to 5(2^{x-3})=4(3^{x+4}) ?

The answer to 5(2^{x-3})=4(3^{x+4}) is x=(2ln(18)-ln(5)+3ln(2))/(ln(2)-ln(3))

Solve for x: 5(2^{x-3})=4(3^{x+4})

The solution is x=(2ln(18)-ln(5)+3ln(2))/(ln(2)-ln(3))

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5 (2^{x - 3}) = 4 (3^{x + 4})

x = \frac{2 ln ( 18 ) - ln ( 5 ) + 3 ln ( 2 )}{ln ( 2 ) - ln ( 3 )}

Solution steps

5 (2^{x - 3}) = 4 (3^{x + 4})

Apply exponent rules

ln (5) + (x - 3) ln (2) = ln (4) + (x + 4) ln (3)

Solve

ln (5) + (x - 3) ln (2) = ln (4) + (x + 4) ln (3) : x = \frac{2 ln ( 18 ) - ln ( 5 ) + 3 ln ( 2 )}{ln ( 2 ) - ln ( 3 )}

x = \frac{2 ln ( 18 ) - ln ( 5 ) + 3 ln ( 2 )}{ln ( 2 ) - ln ( 3 )}

8^{x} + 8^{x - 1} + 8^{x + 1} = 292

(n - 2)^{(n - 2) 2} = 2

2 x^{4} e^{- 2 x} = 0

4^{x + 3} = 64

1.7 \cdot 6^{- 1.7 v} - 6 = 8

What is the answer to 5(2^{x-3})=4(3^{x+4}) ?
The answer to 5(2^{x-3})=4(3^{x+4}) is x=(2ln(18)-ln(5)+3ln(2))/(ln(2)-ln(3))
Solve for x: 5(2^{x-3})=4(3^{x+4})
The solution is x=(2ln(18)-ln(5)+3ln(2))/(ln(2)-ln(3))