What is the answer to 9^{x-1}=4 ?

The answer to 9^{x-1}=4 is x=(ln(2))/(ln(3))+1

Solve for x: 9^{x-1}=4

The solution is x=(ln(2))/(ln(3))+1

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9^{x - 1} = 4

x = \frac{ln ( 2 )}{ln ( 3 )} + 1

Decimal Notation

x = 1.63092 \dots

Solution steps

9^{x - 1} = 4

Apply exponent rules

(x - 1) ln (9) = ln (4)

Solve

(x - 1) ln (9) = ln (4) : x = \frac{ln ( 2 )}{ln ( 3 )} + 1

x = \frac{ln ( 2 )}{ln ( 3 )} + 1

2^{3 x - 1} = 4^{x}

3^{x} + 3^{x - 1} - 3^{x - 2} = 11

1 6^{2 x - 3} = 8

3 e^{2 x} = 2.3

x, z = e^{x y}

What is the answer to 9^{x-1}=4 ?
The answer to 9^{x-1}=4 is x=(ln(2))/(ln(3))+1
Solve for x: 9^{x-1}=4
The solution is x=(ln(2))/(ln(3))+1